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6x^2+49x-17=0
a = 6; b = 49; c = -17;
Δ = b2-4ac
Δ = 492-4·6·(-17)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2809}=53$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-53}{2*6}=\frac{-102}{12} =-8+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+53}{2*6}=\frac{4}{12} =1/3 $
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